F(x+h)=4x^2+3x+4

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Solution for F(x+h)=4x^2+3x+4 equation:


Simplifying
F(x + h) = 4x2 + 3x + 4

Reorder the terms:
F(h + x) = 4x2 + 3x + 4
(h * F + x * F) = 4x2 + 3x + 4
(hF + xF) = 4x2 + 3x + 4

Reorder the terms:
hF + xF = 4 + 3x + 4x2

Solving
hF + xF = 4 + 3x + 4x2

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-1xF' to each side of the equation.
hF + xF + -1xF = 4 + 3x + -1xF + 4x2

Combine like terms: xF + -1xF = 0
hF + 0 = 4 + 3x + -1xF + 4x2
hF = 4 + 3x + -1xF + 4x2

Divide each side by 'F'.
h = 4F-1 + 3xF-1 + -1x + 4x2F-1

Simplifying
h = 4F-1 + 3xF-1 + -1x + 4x2F-1

Reorder the terms:
h = 4F-1 + -1x + 3xF-1 + 4x2F-1

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